Ans. The experiments of faraday and Henry show that whenever the magnetic flux passing through a coil change with time an emf is induced in the coil.
Ans. Magnetic flux is the number of field lines crossing any surface normal to it.
Magnetic flux $\phi_{B}=\vec{B}\,.\,\vec{A}=BA\,cos\theta $
Ans. The magnitude of the induced emf in a coil is equal to the rate of change of magnetic flux through the coil.
$$E=\,-\,N\, \frac{\mathrm{d} \phi_{B}}{\mathrm{d} x}$$
Ans. The polarity of induced emf is such that it tends to produce a current which opposes the change in magnetic flux that produced it.
Ans. The mechanical energy expended in moving the conductor is converted into electrical energy and then into thermal energy.
Ans. When large pieces of conductors are subjected to changing magnetic flux, induced currents are produced in them. Such induced currents are called eddy currents.
Ans. When the magnetic flux through a coil change, an electric current is induced in it.
Here, the flux is proportional to the current ϕ_B I . The constant of proportionality in this is called inductance.
(or) inductance is the ratio of the magnetic flux to current.L = Nϕ/I
Ans. The e.m.f is induced in a single isolated coil due to change of flux through the coil by varying the current through the same coil is known as self-induction
$$ E= - L \: \frac{\mathrm{d} i }{\mathrm{d} t}$$
where L = self-inductance.
Ans. $di = 5-0 = 5 A,dt = 0.1 sec,E= 200 V$
$ E= - L \: \frac{\mathrm{d} i }{\mathrm{d} t}$
$ L=\frac{E}{ \: \frac{\mathrm{d} i }{\mathrm{d} t}}$
$ L=\frac{200}{ \: \frac{ 5}{0.1}}$
$ L= 4\,H$
Ans. $ E= - M\: \frac{\mathrm{d} i }{\mathrm{d} t}=\, \frac{\mathrm{d} \phi }{\mathrm{d} t}$
$\therefore\,\, d\phi\,=\,M. \,di$
$ \, d\phi\,=\,1.5(20-0) \, $
$ \, d\phi\,=\, 30 \, wb$
Ans. The experiments of faraday and Henry show that whenever the magnetic flux passing through a coil change with time an emf is induced in the coil.
Ans. Magnetic flux is the number of field lines crossing any surface normal to it.
Magnetic flux$\phi_{B}=\vec{B}\,.\,\vec{A}=BA\,cos\theta $